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6x^2+6x=432
We move all terms to the left:
6x^2+6x-(432)=0
a = 6; b = 6; c = -432;
Δ = b2-4ac
Δ = 62-4·6·(-432)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10404}=102$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-102}{2*6}=\frac{-108}{12} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+102}{2*6}=\frac{96}{12} =8 $
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